Stamets@lemmy.world to Funny@sh.itjust.works · 8 months agoTell me I'm wrong. TELL ME I'M WRONG.lemmy.worldimagemessage-square31linkfedilinkarrow-up11arrow-down10
arrow-up11arrow-down1imageTell me I'm wrong. TELL ME I'M WRONG.lemmy.worldStamets@lemmy.world to Funny@sh.itjust.works · 8 months agomessage-square31linkfedilink
minus-squaregigachad@sh.itjust.workslinkfedilinkarrow-up0·8 months agoIs it though? Doesn’t it have to be (x)² then? Because -5² = -25 ?
minus-squarepolysexualstick@lemmy.worldlinkfedilinkarrow-up0·8 months agoNo, because what you are doing isn’t x^2 with x=-5. It is -x^2 with x=5.
minus-squareSaledovil@sh.itjust.workslinkfedilinkarrow-up0·8 months agoIf you multiply a negative number with a negative number you get a positive number.
minus-squareCharzard4261@programming.devlinkfedilinkEnglisharrow-up0·8 months agoNo they’re wrong in mathematics too. -5^2 is -25, but -5^2 is not the same as x^2 where x= -5. No brackets needed on x.
minus-squaregigachad@sh.itjust.workslinkfedilinkarrow-up0·edit-28 months agoWell that is not debatable, I am talking about the difference between -5² = -25 and (-5)² = 25
minus-squareSaledovil@sh.itjust.workslinkfedilinkarrow-up0·8 months agoI edited my comment before you posted your comment. You’re right.
minus-squarereliv3@lemmy.worldlinkfedilinkarrow-up0·edit-28 months agoOpen desmos. Graph y = x^2. Then graph y = (x)^2. Recognize that both graphs are identical. Realize the flaw in your argument.
deleted by creator
Is it though? Doesn’t it have to be
(x)²then? Because-5² = -25?No, because what you are doing isn’t x^2 with x=-5. It is -x^2 with x=5.
If you multiply a negative number with a negative number you get a positive number.
No they’re wrong in mathematics too. -5^2 is -25, but -5^2 is not the same as x^2 where x= -5. No brackets needed on x.
Well that is not debatable, I am talking about the difference between
-5² = -25and(-5)² = 25I edited my comment before you posted your comment. You’re right.
Open desmos. Graph y = x^2. Then graph y = (x)^2. Recognize that both graphs are identical. Realize the flaw in your argument.