The definition of this number is that the number of 0s after each 1 is given by the total previous number of 1s in the sequence. That’s why it can’t contain 2 despite being infinite and non-repeating.
Implicitly defining a number via it’s decimal form typically relies on their being a pattern to follow after the ellipsis. You can define a different number with twos in it, but if you put an ellipsis at the end you’re implying there’s a different pattern to follow for the rest of the decimal expansion, hence your number is not the same number as the one without twos in it.
Right and the point of defining this number as a non-repeating sequence 0s and 1s is just to show that non-repetition of digits alone is not sufficient to say a number contains all finite sequences.
You can, it’s literally the way the number is defined.
Defined where ?
It’s implicitly defined here by its decimal form:
The definition of this number is that the number of 0s after each 1 is given by the total previous number of 1s in the sequence. That’s why it can’t contain 2 despite being infinite and non-repeating.
Pi is often defined as 3.141 592 653… Does that mean Pi does not contain any 7s or 8s?
Might very well be :
0.101001000100001000001202002000200002000002 …
Real life, is different from gamified questions asked in student exams.
Implicitly defining a number via it’s decimal form typically relies on their being a pattern to follow after the ellipsis. You can define a different number with twos in it, but if you put an ellipsis at the end you’re implying there’s a different pattern to follow for the rest of the decimal expansion, hence your number is not the same number as the one without twos in it.
assumption ≠ definition
Math kind of relies on assumptions, you really can’t get anywhere in math without an assumption at the beginning of your thought process.
Obviously. But still maths avoids stuff like “I assume the answer is X. QED.”
Right and the point of defining this number as a non-repeating sequence 0s and 1s is just to show that non-repetition of digits alone is not sufficient to say a number contains all finite sequences.